- #1

- 18

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λ = np√((1-cos

^{2}θ)/n

^{2})

If this isn't clear, inside the square root is (1-cos

^{2}θ) divided by n

^{2}. But isn't this whole expression the same as p*sinθ? I would think the top of the square root would equal sin

^{2}θ, then with the square root the n's would cancel. But this would mean that the wavelength doesn't depend on the diffraction index at all. Am I doing something dumb here?