Christoffel symbols for gravitational waves

e^ipi=-1
Messages
5
Reaction score
0

Homework Statement


Determine the Christoffel symbol \Gamma^{t}_{xx} for the metric ds^2 = -c^2dt^2 + (1+h\sin(\omega t))dx^2 + (1-h\sin(\omega t))dy^2 + dz^2

The answer should be: \frac{h\omega}{2} \cos(\omega t)

Homework Equations


For the evaluation we have to use \frac{d^2x^\alpha}{d\tau^2}+\Gamma^\alpha_{\mu\nu}\frac{dx^\mu}{d\tau}\frac{dx^\nu}{d\tau}


The Attempt at a Solution


I keep getting c's where they shouldn't be. I calculated the Euler Lagrange Equation for the time to be:
-2\frac{d^2(ct)}{d\tau^2}-c^{-1}\omega h\cos(\omega t)((\frac{dx}{d\tau})^2 - (\frac{dy}{d\tau})^2) = 0
Which leaves us with the equation of motion
\frac{d^2 t}{d\tau^2}+\frac{1}{2c^2}\omega h\cos(\omega t)((\frac{dx}{d\tau})^2 - (\frac{dy}{d\tau})^2) =0
So the answer is:
\Gamma^{t}_{xx}=\frac{h\omega}{2c^2} \cos(\omega t)
Where have I gone wrong? Also, I don't understand whether you are supposed to take t or ct as the zero'th coordinate and whether it gives a different answer.
 
Physics news on Phys.org
are you sure you're not working in natural units because I get the same answer as you. i don't think it cancels. you could redefine t' = ct but that still gives you factors of c
 
Don't know if you already figured it out but the problem probably wanted it in natural units. Also, when you only have one specific Christoffel symbol to calculate it is much easier to just use the equation for the Christoffel symbols in terms of permutations of first derivatives of the metric; I am sure you know which one this is (too lazy to do all the latex business).
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top