Circuit Analysis: Find i, v Given R1, R2

AI Thread Summary
The discussion revolves around solving a circuit analysis problem involving resistors R1 and R2, with values of 6 ohms and 3 ohms, respectively. The initial calculations yield a voltage of 12V and a current of 1A, but concerns arise regarding the interpretation of the current direction, suggesting the voltage source is absorbing energy. Further analysis using Kirchhoff's laws reveals that the current through R2 is actually 3A, leading to a voltage of 9V across it. Applying Kirchhoff's Voltage Law (KVL) results in a corrected voltage of 21V and a current through R1 of 2A, confirming that the initial current calculation is consistent with the circuit's passive sign convention. The conversation emphasizes the importance of correctly applying KVL and KCL to resolve circuit parameters accurately.
Xkaliber
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Homework Statement



(a) Suppose that R_1 = 6 ohms and R_2 = 3 ohms. Find the current i and the voltage v. See the diagram in the picture.

http://img291.imageshack.us/img291/7638/picturewr3.th.jpg

Homework Equations



Kirchhoff's laws and Ohm's law

The Attempt at a Solution



I got v=12V and i=1A

However, I do not think that this is correct since a positive value for i means the voltage source is absorbing energy instead of supplying it, which does not make sense.
 
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Xkaliber said:
I got v=12V and i=1A

However, I do not think that this is correct since a positive value for i means the voltage source is absorbing energy instead of supplying it, which does not make sense.

Why don't you write out your current loop equations and maybe we can see where you may be confused?
 
First, since the 3 amp current source is in series with R_2, the current through R_2 is 3A. Using Ohm's law, we find the voltage across R_2 to be 9 volts.

Now, KVL around outer loop: -12V - 9V + v = 0 -> v = 21V

KVL around right smaller loop: -9V + 21V - v_1 = 0 -> v_1 = 12V

Using ohm's law, current through R_1 = 2A

KCL @ top middle node: 3A - 2A - i = 0 -> i = 1A

If i does equal 1A, then according to the diagram in the picture, the voltage source is absorbing power since it is in the passive convention.
 
Xkaliber said:
Now, KVL around outer loop:

This could be your problem.

I think what you really want to do is take the equations for the left and right loops, noting that the current through the R1 is the sum of the left and right loop currents.

This should give ou the equations and unknowns that you are looking for.
 
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