Classical Electron Magnetic Moment

AI Thread Summary
The discussion focuses on deriving the classical magnetic moment for an electron with uniform charge and mass distributions, specifically using the formula μs = -(e/2m)S, where S represents the spin angular momentum. The user contemplates whether to assume the charge is distributed over the surface of a sphere and considers integrating over the entire sphere to calculate the magnetic moment. They express confusion regarding the integration process, particularly in relating charge density to the total charge and ensuring the correct powers of r during integration. The user also seeks clarification on the correct formulation of current and the implications of integrating charge density. Overall, the thread highlights the complexities involved in calculating the magnetic moment for a spinning electron.
greeziak
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I'm trying to show that for an electron of uniform charge and mass distributions spinning about a fixed axis that the classical calculation for the magnetic moment is

μs = -(e/2m)S where S is the spin angular momentum.

Now I know that the moment for any given current loop is μ = iA. So should I just be assuming all the charge is at the surface and integrate over the entire sphere? The moment for an orbiting electron is of the same form but with L instead of S, so I think this might be the way to start, but I'm not sure. Thanks.
 
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As of right now I am writing q = ρ2πr as the infinitesimal amount of charge in the current loop with the current being q/T with T, the period, T = 2πr/v. The area in these loops then should be πr2, with the surface integral rdr tacked on from 0 to r. This doesn't seem to work.

Also writing the current as q = ρ2πdr is providing me nothing. In order to get ρ back into -e I'm using ρ * 4pi*r2, which means I need a pi to survive at the end. One last note, before integration the power of r has to be either 1 or 3 to avoid an odd number in the denominator? Any help at this point would be great, thanks.
 
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