Classical Mech - Newtons 2nd. Quad Air Resistance

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Homework Help Overview

The problem involves analyzing the motion of a puck moving up an incline under the influence of gravity and air resistance, described by Newton's second law. The focus is on deriving the puck's velocity as a function of time during its upward journey.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the differential equation governing the motion, with attempts to manipulate it for integration. Questions arise regarding the correct representation of variables and potential integration techniques.

Discussion Status

Some participants have offered guidance on simplifying the equation and correcting potential errors in sign. There is ongoing exploration of how to approach the integration process, with no clear consensus on the next steps yet.

Contextual Notes

Participants are navigating the complexities of integrating a non-linear differential equation, with specific attention to the effects of air resistance and the absence of friction. The original poster expresses uncertainty about the integration method and the implications of their current formulation.

MPKU
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Homework Statement



A puck of mass m is kicked up an incline (angle θ) with initial speed vo. Friction is not present, but air resistance has a magnitude of f(v) = cv2. Solve Newtons second law for the pucks velocity as a function of t on the upward journey. How long does the journey last?

Homework Equations




The Attempt at a Solution



mr'' = -mgsinθ - fquad

mv' = -mgsinθ - cv2 v(hat)

dv/dt = -gsinθ -(c/m)v2 v(hat)

dt = -dv/ (gsin θ -(c/m)v2 v(hat) )


I'm not quite sure how to solve this; perhaps I could rewrite to get a known integral of 1/(1 +x^2) dx, but I don't see how.
 
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You can drop the v(hat), since you've reduced it to scalars, all motion being in the one dimension.
Can you do it from there?
 
I don't think so. Should I just rewrite it as:

dt = -(gsin θ -(c/m)v^2)^-1 dv and integrate?
 
MPKU said:
I don't think so. Should I just rewrite it as:

dt = -(gsin θ -(c/m)v^2)^-1 dv and integrate?
Yes, except that you just made a sign error.
 

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