Classical Mechanics: Two Body Problem

AI Thread Summary
The discussion focuses on deriving the equations of motion for two objects under mutual forces, demonstrating that the center of mass motion is governed by Mddot R=0, indicating no net external force. The relative motion is described by the equation μddot r=F, where μ is the reduced mass. The participants explore the relationships between the positions of the two masses, leading to the expressions r1=R+(m2/M)r and r2=R-(m1/M)r. One user initially struggles with deriving the position equations but finds success by applying the definitions of center of mass and relative position. The thread emphasizes the importance of these concepts in classical mechanics.
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Homework Statement


Consider two objects with masses ##m_1## and ##m_2## exerting forces on each other with magnitude ##F##. If no other net forces act on the objects, they obey the equations of motion

##m_1\ddot r_1=F##, ##m_2\ddot r_2=-F##

Show that the corresponding equations of motion for the centre of mass ##R## and the relative position ##r## of the two objects in terms of the total mass ##M## and the reduced mass ##\mu##, are given by

##M\ddot R=0##, ##\mu\ddot r=F##

and that

##r_1=R+\frac{m_2}{M}r##, ##r_2=R-\frac{m_1}{M}r##

Homework Equations

The Attempt at a Solution



Using the relation where ##F_{12}+F_{21}=0## I said ##m_1\ddot r_1+m_2\ddot r_2=0##. This equates to ##M\ddot R=0## as asked.

To show ##\mu\ddot R=F##, I manipulated ##m_1a_1=-m_2a_2## to get ##a_2=-\frac{m_1}{m_2}a_1##. Then using

##a_{rel}=a_1-a_2=a_1+\frac{m_1}{m_2}a_1=(1+\frac{m_1}{m_2})a_1##

##=\frac{m_2+m_1}{m_1m_2}m_1a_1##, Therefore ##\frac{F}{\mu}=a_{rel}=\ddot r##

And finally ##\mu\ddot r=F##

I can't find a way of finding ##r_1## and ##r_2## as asked however. I tried using ##m_1r_1+m_2r_2=0## but I can't find it as I'm asked. Any help here would be greatly appreciated.
 
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Use the defining equations for the center of mass R and relative position r
 
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Worked a charm cheers!
 
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