Closed integral in electromagnetics

AI Thread Summary
Gauss's Law relates the total charge enclosed by a surface to the closed integral of the electric displacement field (D) over that surface. The equation in question, which equates the total charge to the closed integral of D.ds, is a mathematical expression derived from Gauss's Law. The term Dr refers to the radial component of the electric displacement field, which provides context for the manipulation in the notes. The discussion highlights confusion over the clarity of the notes and the need for better explanations in the study materials. Overall, understanding the relationship between these concepts is crucial for mastering electromagnetics in engineering.
tidesong
Well I'm studying this under engineering but its also maths so I posted this here and hope its in the right forum

The question is: When using Gauss's Law i have this equation in my notes: total charge enclosed by surface = closed integral of ( D .ds) over S

the next line (in my notes) equates this to Dr( closed integral of dS over S)

Is this a mathematical manipulation, or is this due to some law? And is Dr just a constant or does it have some meaning? Thanks.
 
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Ah thanks! If Dr is the radial component then it makes sense! I'm trying to guess what my notes mean too :P
 
Yeah! Our notes are so lousy! Thanks for helping out =)
 
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