A high voltage coaxial cable is used to supply power to an x-ray generator. The cable consists of an inner wire of radius r=1 mm and a thin hollow outer conductor of radius R= 10 mm. The inner wire and the outer shield have the same charge density per unit length of , but opposite charges. Assume that the insulator between the conductors is air. The inner conductor is held at electric potential Vi and the outer conductor is grounded.
a) Use Gauss’ Law to explain why the inner conductor and the inner surface of the outer conductor must have the same charge per unit length.
b) Calculate the field at the surface of the inner wire. (Remember to use cylindrical symmetry.)
c) Write the symbolic form of the field between the two conductors as a function of distance from the axis.
Eq #1: ε0E(2πrL)=λL
Eq #2: E=λ/(2π(ε0)r)
The Attempt at a Solution
A) I honestly, don't know how to use Gauss' Law to prove that the two surfaces have to have the same charge per unit length. However, I do know they have to be the same because the electric field is the constant throughout the inside of the shell. I just don't understand how to represent this mathematically. The only thing I could think of was to use Eq #1 because we know every variable except E and λ. But we do know that E1=E2 and therefore λL should be equal for both sides.
B) The only thing I could think of is to solve for E in terms of λ. I just don't know if thats a reasonable answer or if I should be able to derive λ from some obscure equation I haven't hunted down yet.
C) because I am so lost with the other two I have no idea how to even approach this question. My best guess is to take eq #2 and integrate it with respect to r
Any help would be amazing and much appreciated.