Coefficient of friction (between road and wheels of accelerating truck)

AI Thread Summary
To determine the coefficient of friction (μ) between the road and the wheels of a 1400kg truck accelerating at 2 m/s² with a 4000N engine force, the relevant equations include the normal force (Fn = m * g) and the frictional force (Ff = μ * Fn). The user initially struggled with the variables but was guided to draw a free body diagram and apply Newton's 2nd Law (∑Fx = ma). After calculations, the frictional force was derived from the difference between the product of mass and acceleration and the engine force. The final result for the coefficient of friction was found to be approximately 0.09, illustrating the problem-solving process for similar physics questions. Understanding these calculations is crucial for tackling related physics problems effectively.
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Homework Statement


What is the coefficient of friction between the road and the wheels of a 1400kg truck accelerating at 2 m/s/s if the force applied by the engine to the wheels is 4000N.


Homework Equations


Fn = m * g
Ff = mu * Fn


The Attempt at a Solution


I do not know how to resolve this as I don't know Ff or mu (i.e. two variables)
Any asisstance (not answer) would be appreciated.
 
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First draw a free body diagram.

Then find the resultant force in the horizontal (x) direction.

Newton's 2nd Law states that ∑Fx= ma
 
thanks rock.freak667,
I have found the answer it was on a website called http://www.physics247.com/physics-homework-help/friction-and-weight.php" the answer was 0.09 as is shown here:

mu = Ff/Fn
Ff = (ma) - Fengine
mu = ((ma) - Fengine)/-(mg)
mu = ((1400 * 2) - 4000)/-(1400 * 9.81)
mu = (2800 - 4000)/-13734
mu = -1200/-13734
mu = 0.085...
mu = 0.09
 
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Once you understand the thinking process, as that will allow you do similar problems or slightly more complex ones.
 
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