Coefficient of friction on rock of 0.70

AI Thread Summary
To determine the maximum steepness of a rock slope one can stand on without slipping, the coefficient of friction (0.70) is used in the equation relating friction force and the components of weight. The relevant equation simplifies to μ * cos(θ) = sin(θ), leading to the conclusion that tan(θ) equals the coefficient of friction. By solving for θ, one can find the maximum angle of the slope. The discussion emphasizes understanding the relationship between friction, weight, and slope angle. The final solution involves using a calculator to find the angle based on the derived equation.
zero1520
Messages
4
Reaction score
0
physics help!

:confused: Ok, I have understood every problem we have done so far except this one,

You are wearing shoes that have a coefficient of friction on rock of 0.70. On how steep a rock slope could you stand without slipping?

So far i have gotten:
Fs=Fparallel=
mu*W*costheta = W*sinTheta
w=mg

but if u cancel weights I got:
mu*costheta = sintheta

Im probably completely wrong, but that's what i got.
Thanks in advance.
 
Physics news on Phys.org
well i guess my problem is solving the trig cause i simplified to what he got on that similar problem
 
Looks good to me. The friction force must equal the parallel component of the weight. Good!

Now keep going: \mu cos\theta = sin\theta ==> tan\theta = \mu. Now solve for \theta. (Use your calculator.)
 
ohhh alright i got it, thank you very much
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top