Coefficient of sliding friction without an Fa

AI Thread Summary
To determine the force needed to accelerate a 65kg crate up a 25-degree incline at 7 m/s² with a coefficient of sliding friction of 0.2, it's essential to analyze the forces acting on the crate. The gravitational force must be resolved into components parallel and perpendicular to the incline, requiring the use of trigonometric functions. The frictional force can be calculated using the normal force, which is influenced by the incline angle and the weight of the crate. A free body diagram (FBD) is recommended to visualize these forces and facilitate the calculations. Understanding these dynamics is crucial for solving the problem effectively.
!!!!!!!
Messages
8
Reaction score
0
Problem: A 65kg create is to be accelerated at 7 m/s/s up an incline making an angle of 25 degrees with the horizontal. If the coefficient of sliding friction is .2, what force is needed to accomplish this motion?

Well I've tried manipulating this equation to give me either a Ff or an Fn for the mu=Ff/Fn equation. Problem is where its on an incline, i need Facos25 and Fasin25, but i don't have an Fa, all I am given is a 7m/s/s. I am a bit stuck and need some help here
Thanks in advance
 
Physics news on Phys.org
this is a tough one, anybody?
 
draw a FBD and then break it down into all the forces acting on it
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Yes! Calculating Friction Coefficient
Replies
1
Views
1K
Coefficient of Friction when Normal Force is Reduced [HS]
Replies
5
Views
2K
Mechanical Physics: Coefficient of Friction
Replies
20
Views
3K
Dynamics Skier on a Slope Problem
Replies
9
Views
5K
Applying Newtons Laws: Incline, static friction, kid on sled
Replies
8
Views
2K
Is it possible to pull a wagon without wheels?
Replies
10
Views
2K
Coefficient of Friction question for a cart going down a wooden ramp
Replies
18
Views
3K
How to find Coefficient of Friction w/ Fa and mass?
Replies
5
Views
4K
How to find coefficient of friction of a body sliding down the slope?
Replies
7
Views
2K
Finding Radial Force from Free Body Diagram
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top