Coefficient of static & kinetic friction

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SUMMARY

The coefficient of static friction for an object with a mass of 2.5 kg and a force of 4.90 N required to initiate motion is calculated to be 0.2. This is derived using the formula u = f/N, where f is the force and N is the normal force (calculated as mass times gravitational acceleration). The discussion clarifies that static friction is relevant when determining the force needed to start moving an object, distinguishing it from kinetic friction, which applies once the object is in motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of static and kinetic friction
  • Basic knowledge of force and mass calculations
  • Ability to apply the formula u = f/N
NEXT STEPS
  • Study the differences between static and kinetic friction in detail
  • Learn about the factors affecting friction coefficients
  • Explore real-world applications of friction in engineering
  • Investigate the role of friction in motion dynamics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of friction in motion.

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Homework Statement


If the force needed to start the motion of an object having a mass of 2.5 kg is 4.90 N, what is the coefficient of static friction?

Homework Equations


f = uN
Since u is missing, the formula is u = f/N

The Attempt at a Solution


u = 4.90 N/(2.5 kg X 9.8 m/s2)
u = 4.90 N/24.5 N
u = 0.2

The problem is asking for the coefficient of static friction. I'm not sure if I got the answer for kinetic friction? I know the difference between the two but I don't know why the problem required static friction when it is talking about a moving object.
 
Last edited:
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When an object is at rest it will have static friction and kinetic friction when it is moving. So in order to move an object, you will need to overcome the static friction.
 
semc said:
When an object is at rest it will have static friction and kinetic friction when it is moving. So in order to move an object, you will need to overcome the static friction.

Thanks semc. But is my solution correct?
 

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