Coin Rolling Without Slipping: Physics Final Study Question

[mattmets]

A coin with a diameter of 2.30 cm is dropped onto a horizontal surface. The coin starts out with an initial angular speed of 18.4 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 2.17 rad/s2, how far does the coin roll before coming to rest?


Can anyone help- I'm trying to study for a physics final and I'm getting nowhere! Thanks.

 

[Chen]

Unless I'm missing something here, you can use this formula:

v_f² = v_i² + 2aΔx

Dividing both sides by R², the coin's radius squared, we get:

ω_f² = ω_i² + 2αΔθ

Where α is the coin's angular acceleration, which is negative in this case. From here you can find Δθ and multiplying by R you can find the total distance traveled by the coin.

 

[mattmets]

Great...thanks