- #1
neoncrazy101
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Homework Statement
The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0180 kg and is moving along the x-axis with a velocity of +7.71 m/s. It makes a collision with puck B, which has a mass of 0.0360 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.
http://edugen.wileyplus.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif
Homework Equations
m1vf1x+m2vf2x = m1vo1+m2vo2
0 = Mf1V1sin(65) - M2Vf2sin(37)
M1 = .0180
M2 = .0360
Vo1 = 7.71
Vo0 = 0
The Attempt at a Solution
.018(v)+.036(v) = .018(7.71)
.054v = .13878
v = 2.57. (Terribly wrong)
.018(Vf1)sin(65) - .036(Vf2)sin(37)
My problem is I'm getting so confused as to what I am solving for. I mean, I know I'm solving for the final speeds of puck A and puck B but I'm confused as to how to get there. I'm just plan lost.