- #1
Combining Formulas: Rearrange Equations for F (No Ev)
- Thread starter gareth01422
- Start date
AI Thread Summary
The discussion centers on rearranging two equations to isolate F while eliminating Ev. Participants suggest starting by expressing both equations in terms of Eph and combining them into a single equation. Gareth shares his initial attempt and seeks confirmation on its correctness. Another user confirms the approach and suggests a simplified method for combining the equations. The conversation concludes with Gareth expressing gratitude for the assistance received.
- #2
Firelion
- 16
- 0
Hi,
I´ll help you with the first step:
Both formulas express Eph.
So you have to replace Eph in both of them and write the remaining parts as one equation.
Then the rest should be easy.
Greetings,
Firelion
I´ll help you with the first step:
Both formulas express Eph.
So you have to replace Eph in both of them and write the remaining parts as one equation.
Then the rest should be easy.
Greetings,
Firelion
Last edited:
- #3
- #4
Marta.92
- 1
- 0
Maybe what I'm saying is stupid, but can't you simply put them together?
By doing so, you would have:
hc*t/b= h*f
then you can transform it into
f= hc*t / (b*h)
EDIT: pardon me...I haven't seen that someone had already answered...
By doing so, you would have:
hc*t/b= h*f
then you can transform it into
f= hc*t / (b*h)
EDIT: pardon me...I haven't seen that someone had already answered...
- #5
Firelion
- 16
- 0
Seems perfectly correct to me.
- #6
gareth01422
- 25
- 1
Firelion said:
Brilliant
Thanks for the help guys.
Gareth
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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