Completing Nuclear Reactions: Balancing Charges and Nucleons

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The discussion focuses on completing nuclear reactions by balancing charges and nucleons. Participants express confusion about the notation used for protons, neutrons, and alpha particles in the equations. The correct approach involves ensuring that both the atomic number (Z) and mass number (A) are conserved in the reactions. Clarification is provided on how to interpret the symbols and the importance of correctly identifying the contributions of alpha particles. The conversation emphasizes the need for a systematic approach to solve these types of nuclear equations.
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Homework Statement


Complete the following nuclear reactions, assuming that the unknown quantity signified by a question mark is a single entry. Use the following table for your answers: 0 = gamma, 1 = p, 2 = alpha , 3 = n.

(a) 20X43(alpha,?)21X46

(b) 4X9(?,n)6X12

Homework Equations





The Attempt at a Solution


a) A=46 + 4 - 43 = 7 Z = 21 + 2 - 20 = 3
b) A=12 + 1 - 9 = 4 Z = 6 + 0 - 4 = 2

I have NO idea if I'm doing this correct at all.. I'm really just confused about these types of problems, I need some help.. :[
 
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Hmm the way you've layed this out is quite confusing, are you referring to periodic table style;

20
x
43

sort of layout? With 20 being the number of protons & 43 being the number of nucleons?

Maybe similar to this? http://education.jlab.org/glossary/alphadecay.gif
 
One has to balance the charge (Z, number of protons) and total number of nucleons A, where A = Z + N, and N = number of neutrons.

Remember that the alpha particle is 2He4, i.e. 2 protons and a mass of 4 (2 protons + 2 neutrons).


This (20X43(alpha,?)21X46) =/= (A=46 + 4 - 43 = 7 Z = 21 + 2 - 20 = 3).

Instead try 20X43 + alpha = ? + 21X46, => Z: 20 + 2 = ? + 21, A: ___________
 
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