eng_stud
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Homework Statement
consider a circuit expressed by v(t)= 100cos \omega t
and i(t)=2cos(\omega t+\pi / 3) .
Find the reactance.
Homework Equations
Z=\frac{V}{I} = R+jX
The Attempt at a Solution
Z=\frac{100}{2\angle \pi /3} = 50\angle -\pi /3 = 46 - j19
Does the negative imaginary part mean there is simply more reactance from the capacitor than inductor? Or *only* cap?
thanks!
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