Complex impedance and negative reactance

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SUMMARY

The discussion focuses on calculating the complex impedance of a circuit defined by the voltage function v(t) = 100cos(ωt) and the current function i(t) = 2cos(ωt + π/3). The impedance is determined to be Z = 50∠-π/3, which translates to 46 - j19. The negative imaginary part indicates that the circuit exhibits more capacitive reactance than inductive reactance, though the exact contributions of each component cannot be conclusively determined from the given information.

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Homework Statement



consider a circuit expressed by v(t)= 100cos \omega t
and i(t)=2cos(\omega t+\pi / 3) .

Find the reactance.

Homework Equations


Z=\frac{V}{I} = R+jX

The Attempt at a Solution



Z=\frac{100}{2\angle \pi /3} = 50\angle -\pi /3 = 46 - j19

Does the negative imaginary part mean there is simply more reactance from the capacitor than inductor? Or *only* cap?

thanks!
 
Last edited:
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There is not sufficient information to find if there is only capacitor or there is more capacitive inductance than inductive.
 
That makes sense, thank you!
 

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