Complex Number RLC Series Parallel Voltage and Current Supply

AI Thread Summary
The discussion centers on calculating the source impedances for a complex number RLC series-parallel circuit. The user has derived the impedance for the current source as 4123Ω at an angle of -75.96° and for the voltage source as 4123Ω at 14.04°. There is uncertainty about how to determine the current I2 and how to properly calculate the capacitive reactance (Xc). Participants suggest using Kirchhoff's Voltage Law (KVL) and clarify the need to convert angular frequency into hertz for accurate calculations. The conversation emphasizes the importance of correctly applying formulas and understanding impedance in RLC circuits.
badsanta010
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Hi Everyone.

I have been looking at this questions for a while now and have just hit a brick wall.

I have found the source impedances using the the following

Z of Current source = 1KΩ - jXC

=1000 - j4000Ω = 4123<-75.96°


Z of Voltage source = 4KΩ + jXL

= 4000 + j1000Ω = 4123<14.04°

Correct ?

But from here I am not sure how to approach determining the current I2.

Any kind of guidance would be greatly appreciated.

Thanks
 

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how did you got your value for Xc ?
 
Plus ! you can use KVL in the loop having voltage source !
 
lazyaditya said:
how did you got your value for Xc ?

Using the following formula:

1/jwC

=1/j(25K rads/sec)(10nF)

Thanks
 
shouldn't the angular frequency should be converted into hz ?
 
I could'nt be sure but I assumse that when the formula states Omega it uses its standard form.
 
i think we need to convert it !
 
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