Complex number

  • Thread starter whooi
  • Start date
  • #1
2
0
can someone help me solve this question as fasd as possible??
im really headache wif it....
thx~~

determine the 3 cube roots of 3-i over 3+i giving the result in modulus argument form,express the principal root in the form a+Jb
 

Answers and Replies

  • #2
2
0
hello..anyone can help me out??
 
  • #3
berkeman
Mentor
60,857
11,242
can someone help me solve this question as fasd as possible??
im really headache wif it....
thx~~

determine the 3 cube roots of 3-i over 3+i giving the result in modulus argument form,express the principal root in the form a+Jb

Do not bump your post after only 16 minutes. It is unreasonable to expect fast help all the time here on the PF.

Also, you must show your attempt at a solution before we can be of help. Show us how you would go about simplifying the complex fraction that you are describing....
 
  • #4
35,407
7,278
First off, you're going to want to calculate (3 - i)/(3 + i), to get it in the form a + bi. After that, you should calculate the polar form of this complex number, r(cos[itex]\theta[/itex] + i sin[itex]\theta[/itex]). After that, you can use DeMoivre's Formula to find a cube root, which says that
[tex](r(cos\theta + i sin\theta))^{1/n} = r^{1/n}(cos(\theta/n) + i sin(\theta/n))[/tex].
 

Related Threads on Complex number

  • Last Post
Replies
14
Views
2K
  • Last Post
Replies
12
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
2
Views
1K
P
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
9
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
5
Views
2K
Top