Complex operator in polar coords

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SUMMARY

The discussion focuses on the differentiation of complex functions in polar coordinates, specifically addressing the expression d/dz for z = x + iy. The correct formulation is established as d/dz = 1/2 (d/dx) - i (d/dy), with further elaboration using the chain rule. The transformation involves partial derivatives with respect to polar coordinates, where r = √(x² + y²) and θ = arctan(y/x). The necessity of the function "f" in the differentiation process is also questioned, highlighting the importance of understanding the relationship between Cartesian and polar coordinates.

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  • Familiarity with polar coordinates and their conversion from Cartesian coordinates
  • Knowledge of partial derivatives and the chain rule
  • Basic grasp of complex analysis concepts
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demidemi
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Homework Statement


If z=x + iy, what is d/dz in polar coordinates?


The Attempt at a Solution



I know that expanded,

d/dz = 1/2 (d/dx) - i (d/dy)

Where to go from there?
 
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Use the chain rule:

You have
[tex]\frac{df}{dz}= \frac{\partial f}{\partial x}+ \frac{\partial f}{\partial y}i[/tex]
[tex]= \left(\frac{\partial f}{\partial r}\frac{\partial r}{\partial x}+ \frac{\partial f}{\partial \theta}\right)+ \left(\frac{\partial f}{\partial r}\frac{\partial r}{\partial y}+ \frac{\partial f}{\partial \theta}\frac{\partial \theta}{\partial y}\right)i[/tex]

with, of course, [itex]r= \sqrt{x^2+ y^2}[/itex] and [itex]\theta= arctan(y/x)[/itex].
 
Why is "f" necessary there?

Also, should there be a "partial theta partial x" in the first parentheses?
 
Last edited:

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