Concave Mirror and objects distance

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SUMMARY

The discussion centers on solving a physics problem involving a concave mirror with a focal length of 44 cm, where the image distance is one-fourth the object distance. The equation used is the mirror formula: 1/do + 1/di = 1/f. The participant attempts to manipulate the equation by substituting di with 1/4do, leading to confusion about the correct interpretation of the relationship between object and image distances. The correct approach is to express di as (1/4)do, allowing for the calculation of both object and image distances accurately.

PREREQUISITES
  • Understanding of concave mirrors and their properties
  • Familiarity with the mirror formula: 1/do + 1/di = 1/f
  • Basic algebra skills for manipulating equations
  • Knowledge of focal length and its significance in optics
NEXT STEPS
  • Review the derivation of the mirror formula for concave mirrors
  • Practice problems involving image formation by concave mirrors
  • Explore the relationship between object distance, image distance, and magnification
  • Investigate the effects of varying focal lengths on image properties
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of image formation using concave mirrors.

sheri1987
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Homework Statement


A concave mirror (f = 44 cm) produces an image whose distance from the mirror is one-fourth the object distance.

(a) Determine the object distance.
cm

(b) Determine the (positive) image distance.
cm



Homework Equations



1/do +1/di =1/f do=object distance and di=image distance


The Attempt at a Solution



Since there are two unknowns I thought I could change the equation to 1/do + 1/4do = 1/f...and solve but this wasn't turning out right? am I going about this the wrong way?
 
Physics news on Phys.org
Is 1/4do equal to (1/4)do or 1/(4do)? In any case, if the image distance is one-fourth the object distance, does that mean that di = 4do?
 

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