Solve Heat Conduction Problem: Oven Energy Use & Cost

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The discussion revolves around calculating the energy used by an electric oven operating at 160 °C with an outer surface temperature of 38.6 °C. The formula for heat conduction is applied, with values for thermal conductivity, surface area, temperature difference, and time. The calculated energy expenditure is approximately 4,412,945.581 J, but the user received an incorrect result when submitting this value online. There is a suggestion to ensure the correct numbers are used in the calculations. The conversation highlights the importance of accuracy in thermal calculations for determining energy use and costs.
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The temperature in an electric oven is 160 °C. The temperature at the outer surface in the kitchen is 38.6 °C. The oven (surface area = 1.44 m2) is insulated with material that has a thickness of 0.0249 m and a thermal conductivity of 0.0405 J/(s m C°). (a) How much energy is used to operate the oven for 3.88 hours? (b) At a price of $0.10 per kilowatt-hour for electrical energy, what is the cost (in dollars) of operating the oven?


OK I know to use the Conduction of Heat Through A material on this problem

Q = (k A Delta T) t/ L

After plugging in my values Q = [.045 J/ (s.m.C (degrees)] (1.44m ^2) (160 degrees - 38.6 degrees)(13968 sec) (hours converted to seconds) / 0.0249 m


I get my answer to be 4412945.581 J? This should be my energy value right? The Q in this case is my energy expenditure?


I plugged this answer in for the webbased solution but it was incorrect.

Thanks for ur help

Jason:-p
 
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shaka23h said:
The temperature in an electric oven is 160 °C. The temperature at the outer surface in the kitchen is 38.6 °C. The oven (surface area = 1.44 m2) is insulated with material that has a thickness of 0.0249 m and a thermal conductivity of 0.0405 J/(s m C°). (a) How much energy is used to operate the oven for 3.88 hours? (b) At a price of $0.10 per kilowatt-hour for electrical energy, what is the cost (in dollars) of operating the oven?


OK I know to use the Conduction of Heat Through A material on this problem

Q = (k A Delta T) t/ L

After plugging in my values Q = [.045 J/ (s.m.C (degrees)] (1.44m ^2) (160 degrees - 38.6 degrees)(13968 sec) (hours converted to seconds) / 0.0249 m


I get my answer to be 4412945.581 J? This should be my energy value right? The Q in this case is my energy expenditure?


I plugged this answer in for the webbased solution but it was incorrect.

Thanks for ur help

Jason:-p
Ya got to use da right numbas
 
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