Confunsed about reactions in equilibrium

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To determine the mols remaining at equilibrium for the reaction 1A + 1B <-> 1C + 1D with an equilibrium constant (Keq) of 4, the equation defining Keq is expressed as Keq = [C][D]/[A][B]. Starting with 1 mol of each reactant and product, the changes in concentrations at equilibrium can be represented as x, where x is the amount of A and B that react. Thus, at equilibrium, the concentrations will be [A] = 1 - x, [B] = 1 - x, [C] = x, and [D] = x. Substituting these values into the Keq expression leads to the equation 4 = (x)(x)/((1 - x)(1 - x)). Solving this equation will provide the value of x, allowing for the calculation of the remaining moles of each substance at equilibrium.
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Hey guys, in a reaction like 1A + 1B <-> 1C + 1D, which starts with 1 mol of each molecule (A,B,C,D), how can I find out how many mols will be remaining in equilibrium state?

knowing that the Keq is equal to 4
 
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Write out the equation that defines Keq. Hopefully you will see that, at least together with a very simple and elementary principle of chemistry (as well as of physics) you have all the information needed to solve the problem.
 

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