Confused about direction in angular momentum

AI Thread Summary
The discussion centers on the concept of angular momentum in a system where two balls collide with a rotating stick. Both balls have equal mass and velocity but move in opposite directions, resulting in equal and opposite linear momentum. However, when considering angular momentum, both balls contribute to the stick's rotation in the same direction. Using the right-hand rule for cross products, it's confirmed that both balls have angular momentum pointing in the same direction despite their linear momentum being opposite. Thus, it is possible for two linearly moving objects to have opposite linear momentum but the same angular momentum.
DunWorry
Messages
40
Reaction score
0

Homework Statement


Alright apologies I could not attach an image due to my inexperience of this but its simple to imagine.

Imagine a stick which can rotate about the centre of its axis, perpendicular to its length. I.e the ends can rotate freely in a clockwise, or anti clockwise manner. Now imagine a ball traveling right to left, and hits the top of the stick. At the same time, a ball traveling left to right hits the bottom of the stick. Let's say the balls have same mass and same velocity. The stick will rotate anti clockwise.

The balls will have equal and opposite LINEAR momentum, but do they have equal and opposite angular momentum relative to the rotational axis of the stick? angular momentum is L = r x mv = Iw. For an object traveling in linear motion relative to some origin to find the angular momentum we use L = r x mV. I thought mV was just its linear momentum, so it should be opposite, but then again both the balls are helping the stick rotate in the same direction, so does that mean they have the same direction in terms of angular momentum?
 
Physics news on Phys.org
Angular momentum is same at every point in the orbit.
 
DunWorry said:
For an object traveling in linear motion relative to some origin to find the angular momentum we use L = r x mV.
Right.
I thought mV was just its linear momentum, so it should be opposite, but then again both the balls are helping the stick rotate in the same direction, so does that mean they have the same direction in terms of angular momentum?
Yes. Actually figure out the direction of the angular momentum for each ball using the right hand rule for cross products. You'll find that the angular momentum of each ball points in the same direction.
 
You can use the right-hand-rule to determine the direction of the result of the cross products r x v. If the directions for both are the same, then their angular momenta will also point in the same direction.

Edit: Doh! Doc Al got there ahead of me!
 
Ahhhhh, TRUE I didnt think of the right hand rule. So am I correct in thinking that two linearly moving objects can have opposite linear momentum but same angular momentum?
 
Yes!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top