Convergence of vacuum state of Klein Gordon field in a box

In summary, the Klein Gordon field in a confined box will converge to the vacuum state as the box size decreases to zero. This phenomenon can be observed through the reduction of the energy levels and the increasing number of zero energy states in the field. The convergence to the vacuum state is significant in understanding the behavior of quantum fields in confined spaces and has implications in various fields such as quantum mechanics and cosmology.
  • #1
maverick280857
1,789
4
Hi

I've been reading through the book "Quantum Field Theory: A Tourist Guide for Mathematicians" by George B. Folland. On page 101, he describes the construction of a scalar field "in a box" [itex]\mathbb{B}: \left[-\frac{1}{2}L,\frac{1}{2}L\right]^3[/itex] in [itex]\mathbb{R}^3[/itex]. Here [itex]\bf{p}[/itex] lies in the lattice:

[tex]\Lambda = \left[\frac{2\pi}{L}\mathbb{Z}\right]^3[/tex]

the field being given by

[tex]\Phi(t,{\bf{x}) = \sum_{\Lambda}\frac{1}{\sqrt{2\omega_{p}L^3}}(e^{ip\cdot x - i\omega_{p}t}A_{p} + e^{-ip\cdot x + i\omega_{p}t}A_{p}^{\dagger})[/tex]

Suppose we apply the operator [itex]\Phi(t,{\bf{x}})[/itex] to the vacuum state:

[tex]\Phi(t,{\bf{x}})|0,0,\ldots\rangle = \sum_{\Lambda}\frac{1}{\sqrt{2\omega_{p}L^3}}e^{-ip\cdot x + i\omega_{p}t}|0,0,\ldots,0,1,0,\ldots\rangle[/tex]

(with the 1 in the [itex]p^{th}[/itex] place).

The author goes on to say that

The square of the norm of this alleged vector is [itex]\sum_{\Lambda}1/2(|{\bf{p}}|^2+m^2)[/itex], which is infinite (by comparison to [itex]\int_{\mathbb{R}^3}d{\bf{p}}/(|{\bf{p}}|^2+m^2) = 4\pi\int_{0}^{\infty} r^{2}dr/(r^2 + m^2)[/itex])...

The way out is to interpret [itex]\Phi[/itex] as a operator-valued distribution rather than an operator-valued function.

I get it so far...

That is, [itex]\Phi[/itex] is the linear map that assigns to each compactly supported [itex]C^{\infty}[/itex] function [itex]\chi_{1}[/itex] on [itex]\mathbb{R}[/itex] and each [itex]C^{\infty}[/itex] [itex]\Lambda[/itex]-periodic function [itex]\chi_{2}[/itex] on [itex]\mathbb{R}^3[/itex] the operator

[tex]\int_{\mathbb{B}}\int_{\mathbb{R}}\Phi(t,{\bf{x}})\chi_{1}(t)\chi_{2}({\bf{x}})dt d{\bf{x}} = \sum_{\Lambda}\frac{1}{\sqrt{2\omega_{p}L^3}}\left[\hat{\chi}_{1}(\omega_{p})\hat{\chi}_{2}(-p)A_{p} + \hat{\chi}_{1}(-\omega_{p})\hat{\chi}_{2}(p)A_{p}^{\dagger}\right][/tex]

with the obvious interpretation of the Fourier coefficients [itex]\hat{\chi}_{1}[/itex] and [itex]\hat{\chi}_{2}[/itex]. The rapid decay of these coefficients as [itex]|{\bf{p}}|\rightarrow\infty[/itex] guarantees that this series converges nicely as an operator on the finite-particle space [itex]\mathcal{F}_{s}^{0}(\mathcal{H})[/itex].

I have a few questions here:

1. Have we introduced the two functions [itex]\chi_{1}[/itex] and [itex]\chi_{2}[/itex] as a means to redefine the notion of convergence of the operator [itex]\Phi(t,{\bf{x}})[/itex]?

2. If yes, what is the motivation for such a definition?

3. What is [itex]\mathcal{F}_{s}^{0}(\mathcal{H})[/itex] really?

Thanks.
 
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  • #2
maverick280857 said:
I have a few questions here:

1. Have we introduced the two functions [itex]\chi_{1}[/itex] and [itex]\chi_{2}[/itex] as a means to redefine the notion of convergence of the operator [itex]\Phi(t,{\bf{x}})[/itex]?
No, the point is that [itex]\Phi(t,{\bf{x}})[/itex] is not an operator. The only way to get an operator from it is to "smear" it by integrating it against a function. This results in a different operator for every choice of function. Here the author is just using two different functions to smear in time and space.

maverick280857 said:
3. What is [itex]\mathcal{F}_{s}^{0}(\mathcal{H})[/itex] really?
Fock space. Basically get the Hilbert space for a Klein-Gordon particle, attach the Hilbert space for two particles and so on, until you have a Hilbert space which can deal with any particle number. It's all the Hilbert spaces for different particle numbers put together.
 
  • #3
DarMM said:
No, the point is that [itex]\Phi(t,{\bf{x}})[/itex] is not an operator. The only way to get an operator from it is to "smear" it by integrating it against a function. This results in a different operator for every choice of function. Here the author is just using two different functions to smear in time and space.

Can you please elaborate on that?
 
  • #4
maverick280857 said:
Can you please elaborate on that?
The quantum field operator isn't an operator. It simply gives you operators when you integrate it against a function. Just like the dirac delta isn't a function, but gives you a number when integrated against a function.
 
  • #5
DarMM said:
The quantum field operator isn't an operator. It simply gives you operators when you integrate it against a function. Just like the dirac delta isn't a function, but gives you a number when integrated against a function.

Ok, so its a distribution. Where can I read more about the connection between quantum fields and distributions? More like an expository article/book..
 
  • #6
http://home.uchicago.edu/~seifert/geroch.notes/ .
 
Last edited by a moderator:
  • #7
Thanks, I'll take a look at these.
 

1. What is the Klein Gordon field?

The Klein Gordon field is a mathematical representation of a quantum field that describes the behavior of spinless particles, such as scalar bosons. It is a relativistic field theory that combines elements of classical mechanics, quantum mechanics, and special relativity.

2. What is the vacuum state of the Klein Gordon field?

The vacuum state of the Klein Gordon field refers to the lowest energy state of the field, where no particles are present. In other words, it is the state with the lowest possible energy and no excitations.

3. What is convergence in the context of the vacuum state of the Klein Gordon field in a box?

In this context, convergence refers to the behavior of the Klein Gordon field as the size of the box it is contained in approaches infinity. As the box size increases, the field approaches its vacuum state and the behavior of the field becomes more stable and predictable.

4. How does the convergence of the vacuum state of the Klein Gordon field in a box relate to quantum field theory?

The convergence of the vacuum state in the Klein Gordon field is an important concept in quantum field theory. It allows us to study the behavior of the field in an infinite space, which is necessary for understanding fundamental principles and making accurate predictions in quantum mechanics.

5. What are the implications of the convergence of the vacuum state of the Klein Gordon field in a box?

The convergence of the vacuum state has important implications for understanding the behavior of quantum fields in different physical systems. It allows us to make accurate predictions about the behavior of the field in an infinite space, which is necessary for many practical applications in physics and engineering.

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