Convert tensor from cartesian to cylindrical coordinate

ngkamsengpeter
Messages
193
Reaction score
0

Homework Statement


Given the tensor
<br /> F_{\mu \nu }= <br /> \left[ \begin{array}{cccc} 0 &amp; -E_{x} &amp; -E_{y} &amp; -E_{z} \\ E_{x} &amp; 0 &amp; B_{z} &amp;-B_{y} \\E_{y} &amp; -B_{z} &amp; 0 &amp; B_{x} \\E_{z} &amp; B_{y} &amp; -B_{x} &amp; 0 \end{array} \right]<br />
<br /> F^{\mu \nu }F_{\mu \nu }=2(B^2-\frac{E^2}{c^2})<br />
and metric tensor
<br /> n_{\mu \nu }= <br /> \left[ \begin{array}{cccc}c^2&amp; 0 &amp; 0 &amp; 0 \\ 0 &amp; -1 &amp; 0 &amp; 0 \\ 0 &amp; 0 &amp; -r^2 &amp; 0 \\ 0 &amp; 0 &amp; 0 &amp; -1 \end{array} \right]<br />

How to convert it into cylindrical coordinates, that is in terms of Eθ,Ez,Er
More info of this tensor can be viewed at http://en.wikipedia.org/wiki/Electromagnetic_tensor

Homework Equations


The Attempt at a Solution



I try to convert it using the transformation matrix and tensor transformation rule but it turns out that
<br /> F^{\mu \nu }F_{\mu \nu }≠2(B^2-\frac{E^2}{c^2})<br />

Can anyone give me some idea how to solve this?
Thanks.

Homework Statement


Homework Equations


The Attempt at a Solution

 
Physics news on Phys.org
No one can help?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top