robertjford80
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Homework Statement
Do you see how y gets converted to csc? I don't get that. I would y would be converted to sin in polar coordinates.
Converting cartesian to polar coordinates in multiple integrals
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Do you see how y gets converted to csc? I don't get that. I would y would be converted to sin in polar coordinates.
Karamata
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<deleted>
robertjford80
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thanks, I got it.
robertjford80
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I need to see what Karmata wrote again, if anyone knows I would appreciate it.
robertjford80
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still needing
Karamata
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Hi robertjford80!
I deleted my post because there was error in him (oh, bad English)
But, look at picture.
They said [itex]\int_0^6 \int_0^y x \mbox{d}x\mbox{d}y[/itex], that is yellow region (x from 0 (parallel y-axes) to x=y, y from 0 to 6). [itex]r[/itex] is moving from [itex]r=0[/itex] to y=6, so, [itex]y= 6= r \sin \theta \Rightarrow r = \dfrac{6}{\sin \theta} = 6 \csc \theta[/itex]
I deleted my post because there was error in him (oh, bad English)
But, look at picture.
They said [itex]\int_0^6 \int_0^y x \mbox{d}x\mbox{d}y[/itex], that is yellow region (x from 0 (parallel y-axes) to x=y, y from 0 to 6). [itex]r[/itex] is moving from [itex]r=0[/itex] to y=6, so, [itex]y= 6= r \sin \theta \Rightarrow r = \dfrac{6}{\sin \theta} = 6 \csc \theta[/itex]
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robertjford80
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ok, thanks, I got it. this so far has been one of the most difficult concepts in calculus to understand but I'm slowly getting it.