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Converting cartesian to polar coordinates in multiple integrals

  1. May 25, 2012 #1
    1. The problem statement, all variables and given/known data

    Screenshot2012-05-25at53737AM.png

    Do you see how y gets converted to csc? I don't get that. I would y would be converted to sin in polar coordinates.
     
  2. jcsd
  3. May 25, 2012 #2
    <deleted>
     
  4. May 25, 2012 #3
    thanks, I got it.
     
  5. May 25, 2012 #4
    I need to see what Karmata wrote again, if anyone knows I would appreciate it.
     
  6. May 26, 2012 #5
    still needing
     
  7. May 26, 2012 #6
    Hi robertjford80!

    I deleted my post because there was error in him (oh, bad English)

    But, look at picture.

    They said [itex]\int_0^6 \int_0^y x \mbox{d}x\mbox{d}y[/itex], that is yellow region (x from 0 (parallel y-axes) to x=y, y from 0 to 6). [itex]r[/itex] is moving from [itex]r=0[/itex] to y=6, so, [itex] y= 6= r \sin \theta \Rightarrow r = \dfrac{6}{\sin \theta} = 6 \csc \theta[/itex]
     

    Attached Files:

  8. May 26, 2012 #7
    ok, thanks, I got it. this so far has been one of the most difficult concepts in calculus to understand but I'm slowly getting it.
     
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