Converting stress-strain curve to shear stress-shear strain

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Discussion Overview

The discussion revolves around the conversion of a stress-strain curve obtained from a uniaxial tension test of a crystalline metal material into a corresponding shear stress-shear strain curve. Participants explore both the elastic and plastic regions of the material's behavior, seeking methods to derive the shear properties from the given tensile data.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • Participants discuss using the elastic modulus and Poisson ratio to calculate the shear modulus from the tensile test data.
  • Some participants propose that the elastic shear strains can be derived using the relationship τ/G, where τ is the shear stress and G is the shear modulus.
  • There is uncertainty regarding how to address the plastic shear strains, with participants expressing a need for further exploration of the equations involved.
  • One participant notes that it is challenging to determine plastic shear strains directly from experimental measurements due to the nature of uniaxial loading, which does not yield pure shear stress conditions.
  • Another participant introduces the concept of von Mises plasticity, suggesting that the yield stress in pure shear can be related to the known uniaxial yield stress through the equation τ = σ_y / √3, assuming von Mises conditions apply.

Areas of Agreement / Disagreement

Participants generally agree on the approach to derive elastic properties but express differing views on how to handle the plastic region of the shear stress-shear strain curve. The discussion remains unresolved regarding the methodology for the plastic region.

Contextual Notes

Limitations include the dependence on assumptions related to material behavior under plasticity and the inability to directly measure pure shear stress from uniaxial loading conditions.

turpy
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Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
 
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turpy said:

Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
You use the tensile test to determine the Young's modulus and the poisson ratio. Then you use your equation to calculate the shear modulus G from these. Then you plot shear stress vs shear strain with a slope of G.

Chet
 
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Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
 
turpy said:
Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
 
Chestermiller said:
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
If there is a way of doing it in the plastic region, I have not been able to figure out how. It certainly can't be done directly from the experimental measurements because, for all possible plane orientations within the sample, with this kind of uniaxial loading, there is no orientation in which there is a pure shear stress on the plane. There is always a normal component of the stress (except, of course, at 90 degrees to the load, where the shear stress is zero).

Chet
 
In the same way that 3D elasticity tells you G, based on E and \nu, plasticity (von Mises) tells you that the material will "yield" in pure shear at a value of \tau_y, which is known, based on your known uniaxial yield stress, \sigma_y. This value is:
\tau=\frac{\sigma_y}{\sqrt{3}}

Again, the assumption there is von Mises plasticity.

Hope that helps
 
Last edited:

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