Converting stress-strain curve to shear stress-shear strain

AI Thread Summary
To convert a stress-strain curve from a uniaxial tension test into a shear stress-shear strain curve for crystalline metals, the elastic modulus (E) and Poisson's ratio (v) are first used to calculate the shear modulus (G). The elastic shear stress can be derived using the relationship τ = Gγ, while the plastic shear stress is determined using the von Mises yield criterion, where τ_y = σ_y/√3. The challenge lies in accurately representing the plastic region, as uniaxial loading does not yield pure shear stress conditions. Further exploration of the equations is necessary to address the plastic shear strains effectively. Understanding these conversions is crucial for material behavior analysis under different loading conditions.
turpy
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Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
 
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turpy said:

Homework Statement


For a crystalline metal material
- Elastic modulus E
- Poisson ratio v
- A table with test data of stresses vs. total strains, from a monotonic uniaxial tension test, which generates a stress-strain curve.

How would you use this data to find the corresponding pure shear stress-strain curve?

Homework Equations


ε_elastic = (σ/E)
γ_elastic = (τ/G)
G=E/[2*(1+v)]

The Attempt at a Solution


Using the crystal structure of metal, the normal stresses from the table could be converted to shear stresses via the τ_crss equation (http://virtualexplorer.com.au/special/meansvolume/contribs/wilson/Critical.html )

Then, the elastic shear strains can be obtained from τ/G. But what about the plastic shear strains? This is where I'm stuck. Hints/help would be highly appreciated!
You use the tensile test to determine the Young's modulus and the poisson ratio. Then you use your equation to calculate the shear modulus G from these. Then you plot shear stress vs shear strain with a slope of G.

Chet
 
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Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
 
turpy said:
Hi Chet,
Thanks for the response. That covers the linear elastic region of the shear stress-shear strain curve, but what about the plastic region?
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
 
Chestermiller said:
I don't have the answer to this immediately up my sleeve. I want to spend a little time playing with the equations.

Chet
If there is a way of doing it in the plastic region, I have not been able to figure out how. It certainly can't be done directly from the experimental measurements because, for all possible plane orientations within the sample, with this kind of uniaxial loading, there is no orientation in which there is a pure shear stress on the plane. There is always a normal component of the stress (except, of course, at 90 degrees to the load, where the shear stress is zero).

Chet
 
In the same way that 3D elasticity tells you G, based on E and \nu, plasticity (von Mises) tells you that the material will "yield" in pure shear at a value of \tau_y, which is known, based on your known uniaxial yield stress, \sigma_y. This value is:
\tau=\frac{\sigma_y}{\sqrt{3}}

Again, the assumption there is von Mises plasticity.

Hope that helps
 
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