Cooling heated gas under pressure with water

Click For Summary

Discussion Overview

The discussion revolves around a theoretical problem involving the cooling of heated gas under pressure using water. Participants explore the implications of injecting water into a thermally insulated spherical container filled with air at high temperature and pressure, aiming to understand the resulting temperature and pressure changes.

Discussion Character

  • Theoretical exploration
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Peter poses a question about how much water is needed to cool air from 1000 F to 500 F in a 10 in3 container at 100 psi, considering the effects of steam pressure.
  • Peter clarifies that the scenario is theoretical and simplified for easier calculations, noting that the actual gas is a mixture of air and alcohol.
  • Peter mentions that the requirement to use water for cooling comes from the customer, indicating a specific constraint in the problem.
  • Berkeman asks for clarification on the application and the initial conditions of the gas mixture, seeking to understand the context better.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the specifics of the problem, and multiple viewpoints regarding the theoretical nature of the scenario and the constraints imposed by the customer are present.

Contextual Notes

The discussion lacks detailed assumptions about the properties of the gas mixture and the behavior of water under the specified conditions. The complexity of the real situation is acknowledged but not fully explored.

Who May Find This Useful

This discussion may be useful for individuals interested in thermodynamics, heat transfer, and the behavior of gases under varying conditions, particularly in theoretical contexts.

alabra27
Messages
3
Reaction score
0
If I have a spherical container with volume 10 in^3 filled with air at 1000 F and 100 psi pressure and the container is thermally insulated, how much water (initial T=10 F) I need to inject inside this container to reduce the temperature to 500 F? What would the final pressure inside the container be (The air will reduce pressure due to the cooling, but the water will increase the pressure due to turning into steam)?
I know this is very difficult, so I am looking for approximated and simplified ways to get some ball park numbers.
Thx
Peter
 
Science news on Phys.org
alabra27 said:
If I have a spherical container with volume 10 in^3 filled with air at 1000 F and 100 psi pressure and the container is thermally insulated, how much water (initial T=10 F) I need to inject inside this container to reduce the temperature to 500 F? What would the final pressure inside the container be (The air will reduce pressure due to the cooling, but the water will increase the pressure due to turning into steam)?
I know this is very difficult, so I am looking for approximated and simplified ways to get some ball park numbers.
Thx
Peter

Welcome to the PF. What is the application? Is there only air inside initially? Why are you cooling with water?
 
Hi Berkeman, gald to be here,
There is no application. The question is theorethical. I am working on a problem involved something of comressed heated gas, but it's so complex to explain. This simple example , if answered, will give me the understanding I need to complete my complex project.
Actualy the air in my question in reality is mixture of 10:1 air and alchohol which is then heated inside the container and because of the heating increased the pressure.
I thought air only would make the job easy for the people trying to help me here.
All numbers are not as the real situation but made up for easy calculation.
Appreciate your reply
 
Oh I missed a question.
I must use water for the cooling. This requirement came from the customer.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 8 ·
Replies
8
Views
5K