Cosine Law: Query About Equation | Online Physics Course

  • Thread starter Thread starter paolostinz
  • Start date Start date
  • Tags Tags
    Cosine Law
AI Thread Summary
The discussion revolves around the cosine law equation used to find net forces, specifically the transition from c² = a² + b² - 2ab cosC to c = [a² + b² - 2ab cosC]^(1/2). The notation x^(1/2) is clarified as an alternative to √x, which can lead to confusion. Participants express a desire for clarity on why textbooks might present equations differently, with emphasis on the preference for simpler notation. The conversation highlights the importance of understanding mathematical notation to avoid errors in calculations. Overall, the exchange underscores the need for accessible educational resources to address such confusions.
paolostinz
Messages
25
Reaction score
1
My online physics course is using cosine law to find the net forces on objects. My question is to do with the equation, at first it shows it as : c^2=a^2+b^2-2ab cosC.

From there, it changes to: c=[a^2+b^2-2ab cosC]^1/2.

How and why does this work? Why isn't a square root involved in the operation?
 
Physics news on Phys.org
The notation ##x^{1/2}## is just another notation for ##\sqrt{x}##. Was that your question?
 
Yes, thank you! I see now, it seemed like I was getting the wrong answer when I was doing the original equation, so I thought something else was at play here.

Is there any reason why one would prefer writing the equation this way? I just don't get why my textbook would switch the equation when trying ton present new information.
 
hi paolostinz! :smile:
paolostinz said:
Is there any reason why one would prefer writing the equation this way? I just don't get why my textbook would switch the equation when trying ton present new information.

you mean, writing c instead of c2 ?

or writing (…)1/2 instead of √(…) ?

we usually want c itself, so the fact that it comes from an equation with c2 is a nuisance

(…)n is the general way of writing powers: there's no really good reason for having a special symbol when n = 1/2, and the bar of √, which should really go over the top of the bracket, is a nuisance when the bracket is long :wink:
 
See, that makes sense, it's the little things like this that confuse me most. I wish I had better access to teachers to clear up these type of hiccups. I'm so grateful for this place, thank you everyone!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top