Could someone check my Electronics answers?

  • Thread starter Thread starter Matt.D
  • Start date Start date
  • Tags Tags
    Electronics
AI Thread Summary
The discussion revolves around a request for feedback on answers to an Electronics paper, focusing on circuit calculations and capacitor behavior. Key points include calculations for resistance and potential difference in a closed circuit, the behavior of a capacitor when the switch is opened, and the charge and energy stored in a capacitor charged by a battery. The user provided specific calculations for resistance, charge, and energy but expressed uncertainty about the energy required from the battery compared to the energy stored in the capacitor. The request emphasizes the need for peer assistance in understanding these fundamental concepts in electronics.
Matt.D
Messages
25
Reaction score
0
I've got my final Electronics paper to hand in on Thursday and would be grateful is someone could give my answers the once over :)


Question 1.

The circuit (the attached picture) is connected up with switch S closed. The variable resistor, R is adjusted so that the micro-ammeter reads 100mf (micro farads). For this question you should assume that the micro-ammeter has negligible resistance.

A) With switch S closed,
i) Calculate the resistor of the circuit connected to the battery
ii) State the Potential Difference across the capacitor

B) When switch S is opened and the circuit is not adjusted, state briefly what happens.

C) After switch S is opened the variable resistor, R is gradually adjusted to maintain a constant current 100mf (micro farads). The current is sustained for 10s. After 10s no more current flows.
i) Calculate the charge stored in the capacitor at the moment the switch was opened
ii) Calculate the capacitance of the capacitor.

Question 2. A 10mf (micro farads) capacitor is fully charged by connecting it to a 24 V battery

i) How much charge would be stored in the capacitor?
ii) How much energy would be stored in the capacitor?
iii) Hoe much energy would be required from the battery to charge the capacitor to the 24v level?
iv) Explain why your answer to part (iii) is different from part (ii)



Answer Question 1
A)
i) V = I*R
R = V / I
R = 10V / 100mf
R = 0.1 Ohms

ii) 10Volts

B) When the switch is opened, the circuit is broken and the capacitor begins to drain.


C)
i) Q = DV/Dt
Q = 10V / 10s
Q = Q
Q = 1C

ii) Q/V = C
1/10F = C

Question 2.

A)
i) Q = V *C
Q = 24*10*10^-6
Q = 2.4 * 10^-4 C

ii) E = 1/2 Q*V

E = 1/2 * 2.4x10^-4 *24
E = 2.88 x 10^-3 J

iii) E = 2.88 x 10^-3 J / 24x10^-4 C
E = 12J

iv) ...Really not sure about this! I know its basic so could anyone give me a hint? :)

Thanks - Really appreciate it!
 

Attachments

  • circuit.JPG
    circuit.JPG
    6.8 KB · Views: 468
Last edited:
Physics news on Phys.org
...Would really appreciate it :)
 
Be patient. There is no paid staff here to help you. The members will get around to it when they can.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top