Coulomb's Law: Attraction/Repulsion & Approximate Force Calculation

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    Coulomb's law Law
AI Thread Summary
The discussion revolves around the interaction between two parallel electric dipoles and the application of Coulomb's Law. Participants clarify that the dipoles repel each other due to the nature of their charges, despite initial confusion about potential diagonal attraction. For the force calculation, it's suggested to simplify the problem by treating the dipoles as four individual charges at the corners of a rectangle. The focus is on determining the net forces acting on each charge without needing exact equations for part a. Overall, the conversation emphasizes understanding the basic principles of electric forces and their vector nature.
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Homework Statement


Consider the two parallel electric dipoles shown.


+ (Q) + (Q) | (Distance=d/2)
------------------------------------------x------
- (-Q) - (-Q) | (Distance=d/2)
|-------Distance=X-----------|

a) Do the two dipoles attract or repel from each other
b) Let x>>d. Find an approximate expression for the force between the two dipoles. The expression is in terms of Q,d, and x.
C) sketch the graph of F vs. x.

Homework Equations


Coulombs's law
F=k(q1q2/r2

The Attempt at a Solution


I an completely new to Coulomb's law and dipoles so i don't know how to start.

a) The answer is they repel but i don't get why. I know the top/bottom two charges will repel but won't they attract each other diagonally?
b)Have not attempted. Don't know how to start.
c) Stuck on b. didnt get to this yet
 
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I'm guessing your diagram was supposed to look like this?
Code:
   + (Q)                        + (Q)
   |                            |      (Distance=d/2)
 --x----------------------------x-----------
   |                            |      (Distance=d/2)
   - (-Q)                       - (-Q)
   |-------Distance=x-----------|

Forget about the fact that they're dipoles. Just think about it as a set of four charges at the corners of a rectangle, and figure out the force on each charge. You don't need the exact magnitude and direction (at least not for part a), but you can easily figure out whether there's more force acting to the left or the right on any particular charge.
 
Last edited:
diazona said:
I'm guessing your diagram was supposed to look like this?
Code:
   + (Q)                        + (Q)
   |                            |      (Distance=d/2)
 --x----------------------------x-----------
   |                            |      (Distance=d/2)
   - (-Q)                       - (-Q)
   |-------Distance=x-----------|

Forget about the fact that they're dipoles. Just think about it as a set of four charges at the corners of a rectangle, and figure out the force on each charge. You don't need the exact magnitude and direction (at least not for part a), but you can easily figure out whether there's more force acting to the left or the right on any particular charge.

yes, it should look like that. thanks.

i don't know how to find the forces.
would it be like this? assuming the Q's are: Q1(top left), Q2(top right), -Q3(bottom left), -Q4(bottom right)

FQ1=[k(Q1Q2)/x2]+[k(Q1-Q3)/d2]+[k(Q1-Q4)/(x2+d2)]?

and i do this for Q2, -Q3, -Q4?
 
No equations needed for part a. Just think: the charge at the upper-left is repelled by one of the charges on the right and attracted by another. Which force is greater? Ditto for the charge at the lower-left.
 
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