Coupled Differential Equations

dman12
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Homework Statement



Hi. I am trying to solve a problem on renormalisation group flow and have come across the following coupled equations that I need to solve:

Λ ∂g/∂Λ = b.m

Λ ∂m/∂Λ = -2.m + a.g

Where a and b are just constants. I need to find g(Λ) and m(Λ).

Homework Equations


[/B]
I thought this could perhaps be solved by turning it into a matrix equation and then diagonalising and expressing g(Λ) and m(Λ) as sums of eigenvectors.


3. The Attempt at a Solution

First I found the eigenvalues of the matrix to give:

λ+ = -1 + √(1+ab)
λ- = -1 - √(1+ab)

And then I found the eigenvectors of the operator Λ ∂/∂Λ :

ν+(Λ) = (Λ/μ)λ+ ν+(μ)

Where μ is just some integration constant. A similar expression holds for ν-

I then decomposed:

g(Λ) = α ν+ + β ν-

m(Λ) = γ ν+ + δ ν-

But I don't really know where to go from here? Any help would be greatly appreciated!
 
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dman12 said:

Homework Statement



Hi. I am trying to solve a problem on renormalisation group flow and have come across the following coupled equations that I need to solve:

Λ ∂g/∂Λ = b.m

Λ ∂m/∂Λ = -2.m + a.g

Where a and b are just constants. I need to find g(Λ) and m(Λ).

Homework Equations


[/B]
I thought this could perhaps be solved by turning it into a matrix equation and then diagonalising and expressing g(Λ) and m(Λ) as sums of eigenvectors.


3. The Attempt at a Solution

First I found the eigenvalues of the matrix to give:

λ+ = -1 + √(1+ab)
λ- = -1 - √(1+ab)

And then I found the eigenvectors of the operator Λ ∂/∂Λ :

ν+(Λ) = (Λ/μ)λ+ ν+(μ)

Where μ is just some integration constant. A similar expression holds for ν-

I then decomposed:

g(Λ) = α ν+ + β ν-

m(Λ) = γ ν+ + δ ν-

But I don't really know where to go from here? Any help would be greatly appreciated!

Try a solution of the form
g(x) = A_1 x^r + B_1 x^s, \: m(x) = A_2 x^r + B_2 x^s
where the ##A_i, B_i, r, s## are constants (and I write ##x## instead of ##\Lambda##).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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