Critical mu_s friction value homework.

AI Thread Summary
A user is struggling with a physics homework problem involving a woman pushing a box up an inclined ramp, focusing on calculating the critical value of the static friction coefficient (mu_s). The problem states that if mu_s exceeds a certain value, the box won't move regardless of the applied horizontal force. The user attempted to set up equilibrium equations to find the normal and static friction forces but encountered complexity with trigonometric components due to the horizontal force application. They are unsure if the force should be considered parallel to the ramp or as a straight push, complicating their calculations. The user remains stuck and seeks guidance on how to proceed.
dudeman
Messages
3
Reaction score
0
Hi, I'm working on my homework right now and I've been attempting a problem for a while, I found a post about the same question in the archive but I don't know how to post there, so I figured it was ok to make a new thread. Hope that's ok. The origional post is at https://www.physicsforums.com/showthread.php?t=45394EDIT: here's the actual problem

A woman attempts to push a box of books that has mass up a ramp inclined at an angle (alpha) above the horizontal. The coefficients of friction between the ramp and the box are (mu_k) and (mu_s). The force F applied by the woman is horizontal.

If (mu_s) is greater than some critical value, the woman cannot start the box moving up the ramp no matter how hard she pushes. Calculate this critical value of (mu_s).

I tried setting it up as an equilibrium with the net force in both directions, then solving for the normal force and the static friction force in that situation. Then to get mu_s(coefficent of static friction) I thought I could take the F_s/n = mu_s.

But that resulted in some huge long crazy thing with sines + cosines over more stuff, which ultimately didn't work.
 
Last edited:
Physics news on Phys.org
update, so I've been thinking, it says the force is horizontal, would that mean that the force is parallel ot the clope of the ramp, or stright from the left or right, meaning that I would have to separate it into it's components. Also no change in status. I'm still stuck as before.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top