Cross sectional area of cylinder?

AI Thread Summary
The discussion revolves around understanding the cross-sectional area of a cylinder in the context of Darcy's Law, which describes fluid flow in porous media. Participants express confusion about the relationship between Darcy's Law and the cross-sectional area, questioning the type of cylinder and the method of cross-sectioning. There is a call for a graph and clearer explanations to aid understanding, highlighting a lack of responses to the initial query. The connection between volumetric flow rate, flow area, and fluid dynamics is emphasized, though practical application to a cylinder remains unclear. Overall, the conversation seeks clarity on how Darcy's Law applies to calculating the cross-sectional area of a cylinder.
ElectricMile
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using Darcys law...

...what is Cross sectional area of cylinder?
 
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1.Who's Darcy...?
2.What kind of cylinder are you talking about...?
3.How is that cross-section performed...?

A graph and an explanation about this guy & his law wuld be helpful for everyone.Don't u find weird that nobody gave a reply in 4 hours...?

Daniel.
 
How does the study of waterflow through porous media relate to the cross sectional area of a cylinder (which would depend on how you take the cross section)?
 
Here's what I found googling "Darcy's Law":

"Darcy's Law is a generalized relationship for flow in porous media. It shows the volumetric flow rate is a function of the flow area, elevation, fluid pressure and a proportionality constant. It may be stated in several different forms depending on the flow conditions. Since its discovery, it has been found valid for any Newtonian fluid. Likewise, while it was established under saturated flow conditions, it may be adjusted to account for unsaturated and multiphase flow. The following outlines its common forms and assumes water is the working fluid unless otherwise stated."

I don't know how you would use that to find the cross sectional area of a cylinder!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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