Cycloid Particle: Finding Velocity and Acceleration

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The discussion focuses on a particle moving in a cycloidal path defined by the equations x = Rsin(wt) and y = Rcos(wt) + R. The participant successfully sketched the cycloid but struggled with calculating instantaneous velocity and acceleration at the maximum and minimum y-values. They correctly identified that the maximum y-value occurs at y = 2R and the minimum at y = 0, but were confused about the corresponding velocities, suggesting that instantaneous velocity at maximum y is zero and at minimum y is infinite. Clarifications were provided regarding the relationship between the tangent of the curve and the velocity vectors, emphasizing the need to evaluate the time instants for maximum and minimum y to find accurate velocity values. Understanding the differentiation of the position equations is crucial for resolving the participant's conceptual errors.
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Homework Statement



A particle moves in a plane according to

x= Rsin(wt) = wRt
y= Rcos(wt) + R

where w and R are constants. This curve, called a cycloid, is the path traced out by a point on the rim of a wheel which rolls without slipping along the x-axis.

Question:
(a) Sketch the path.

(b) Calculate the instantaneous velocity and acceleration when the particle is at its maximum and minimum value of y.


Homework Equations




x= Rsin(wt) = wRt
y= Rcos(wt) + R


The Attempt at a Solution




I drew up the path of the particle, as a cycloid of course. No problem with that.
I am having problems understand part b, with relation to the curve.

I differentiated the given equations wrt to x.

i.e.
dy/dt = -Rw sin (wt)
dx/dt= Rw cos (wt) + wR

then i proceed to find dy/dx = [Rw sin (wt)]/[Rw cos (wt) + wR]


Ymaximum should be 2R (diameter of the rim of the wheel)

I also went ahead to find values of x which corresponds to the maximum and minimum values of y.
Values of X for maximum Y = 0, 2pie, ...
Values of X for minimum Y = pie, 3pie, ...


Instantaneous velocity is tangent of the curve of a position time graph, which is it the same as the graph i drew out?


Then back to the original question, the instantaneous velocity at maximum y is therefore 0? and instantaneous velocity at minimum y is infinity?



I know I have a conceptual error somewhere but I just can't figure it out.
 
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shyta said:

Homework Statement



A particle moves in a plane according to

x= Rsin(wt) = wRt
y= Rcos(wt) + R


You mean x=Rsin(wt) + wRt, don't you?

shyta said:

Instantaneous velocity is tangent of the curve of a position time graph, which is it the same as the graph i drew out?

Your graph shows y in terms of x. Both the velocity and the acceleration are vectors. vx=dx/dt, vy=dy/dt. The tangent of this graph shows the direction of velocity at the given point. The x and y components of the acceleration are the time-derivatives of vx and vy, respectively.

You have found already that
dy/dt = -Rw sin (wt)
dx/dt= Rw cos (wt) + wR

vx=dx/t and vydy/dt.
At what time instants is y maximum or minimum? Find and plug in the values for t in the equations for vx and vy.

ehild
 
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