Cyclotron Resonance (Solid State Physics)

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Homework Help Overview

The discussion revolves around cyclotron resonance in the context of solid state physics, specifically focusing on a spheroidal energy surface defined by a given energy equation. Participants are exploring the relationship between the energy surface and the dynamics of Bloch electrons under a magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the computation of a cross product involving momentum space vectors and coordinate space vectors. There is an attempt to clarify the relationship between these vectors and how to proceed with the calculations.

Discussion Status

The conversation includes attempts to understand the mathematical relationships involved and the challenges faced in mixing different types of vectors. Some participants express curiosity about the problem and share their experiences related to similar questions.

Contextual Notes

One participant notes a lack of progress on the problem, indicating it was previously encountered in a test. There is also mention of the time elapsed since the original post, suggesting a potential gap in ongoing engagement.

cepheid
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Homework Statement



Cyclotron resonance for a spheroidal energy surface. Consider the energy surface

\epsilon(\mathbf{k}) = \hbar^2 \left( \frac{k_x^2 + k_y^2}{2m_t} + \frac{k_z^2}{2m_l} \right)​

where mt is the transverse mass parameter and ml is the longitudinal mass parameter. A surface on which \epsilon(\mathbf{k}) is constant will be a spheroid. Use the equation of motion with \mathbf{v} = \hbar^{-1} \nabla_{\mathbf{k}} \epsilon to show that \omega_c = eB/(m_l m_t)^{1/2}c when the static magnetic field B lies in the xy plane.

Homework Equations



Dynamics of Bloch Electrons

The equation of motion for an electron subject to the periodic potential of a crystal lattice is

\hbar \frac{d\mathbf{k}}{dt} = -\frac{e}{c}\mathbf{v} \times \mathbf{B} \ \ \ \textrm{cgs}\hbar \frac{d\mathbf{k}}{dt} = -e\mathbf{v} \times \mathbf{B} \ \ \ \textrm{SI}

The Attempt at a Solution



\mathbf{v} = \hbar^{-1} \nabla_{\mathbf{k}} \epsilon(\mathbf{k}) = \hbar^{-1} \left( \hat{k}_x \frac{\partial}{\partial k_x} + \hat{k}_y \frac{\partial}{\partial k_y} + \hat{k}_z \frac{\partial}{\partial k_z} \right) \hbar^2 \left( \frac{k_x^2 + k_y^2}{2m_t} + \frac{k_z^2}{2m_l} \right)​

= \hbar \left( \hat{k}_x \frac{k_x}{m_t} + \hat{k}_y \frac{k_y}{m_t} + \hat{k}_z \frac{k_z}{m_l} \right)​

Apply the equation of motion with

\mathbf{B} = B_x \hat{x} + B_y \hat{y}

\frac{d\mathbf{k}}{dt} = -\frac{e}{c}\left( \hat{k}_x \frac{k_x}{m_t} + \hat{k}_y \frac{k_y}{m_t} + \hat{k}_z \frac{k_z}{m_l} \right) \times (B_x \hat{x} + B_y \hat{y})

Right so, um how am I supposed to proceed to compute such a cross product? :rolleyes:
 
Last edited:
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so, you have problem with mixing coordinate space vectors with momentum space vectors. you can still do this as long as you know what is
\hat k_i \times \hat x_j
at the moment I can't recall what this is... but i think \hat k_i \perp \hat x_i
should try the momentum space representation of the position operator as a guide to convert them, perhaps?
 
Did you ever figure this out?
 
Last edited:
I just had this on a test, but didn't get it done so as you can imagine i was curious about it. Also, just realized you put this on here a year ago so nevermind.
 

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