I Cylinder supported by two rollers

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The discussion focuses on calculating the static reaction force on a cylinder supported by two rollers, emphasizing that this force is inversely proportional to the cosine of the contact angle. As the contact angle approaches 90 degrees, the reaction force can exceed the weight of the cylinder, raising questions about the relationship between the weight and the reaction forces. Participants clarify that reaction force components can oppose each other, leading to higher non-opposing forces than the weight itself. The concept of forces lacking a "source" is highlighted, distinguishing between forces and energy, and explaining that large forces can arise from small applied forces in various mechanical scenarios. Understanding these principles is crucial for accurately analyzing the mechanics of the system.
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I'm trying to calculate the static reaction force on cylinder supported by two rollers due to the weight of the cylinder. I found that the reaction force is inversely proportional to the Cosine of the contact angle, but what does it mean? when the contact angle is close to 90 degrees is the reaction force much higher then the weight of the cylinder? if the weight of the cylinder is the source of the reaction forces how can it be lower than the reaction forces?
 

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Hi dada, :welcome: !

Are you aware that certain components of the reaction force oppose each other ?

And: is this homework ?
 
But still -the non opposing reaction components are much higher then their "source" - the weight of the cylinder. I just wonder how can it be (and its not homework..)
 
Compare it with holding up a weight hanging from the middle of a wire by pulling apart the two ends. There's a ##1/\cos## in there too ...
 
dada1 said:
the source of the reaction forces
This is the Trojan Horse in your question. Forces don't have a "source". Energy and Work have sources. Cause and effect follow a logical direction and Energy 'flows'. Forces are merely 'there'. Large forces can turn up when a small force is applied in many circumstances. That's the basis of most tools we use from levers to screw jacks.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...

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