Cylindrical shells trouble integrating

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The discussion focuses on using the method of cylindrical shells to find the volume generated by rotating the region bounded by the curves y=e^(-x^2), y=0, x=0, and x=1 around the y-axis. The graph of y=e^(-x^2) is described as a bell-shaped curve that decreases rapidly, also known as a Gaussian curve. To evaluate the integral of 2(pi)x*e^(-x^2), a substitution method is suggested, using u=-x^2, which simplifies the integral. After substitution, the integral can be evaluated using the power rule or numerically with a calculator. This approach provides a clear path to solving the volume problem using cylindrical shells.
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i'm told to use the method of cylindrical shells to find the volume gnerated by rotating the region bounded these curves about the y axis:
y=e^(-x^2)
y=0
x=0
x=1
Couple questions. What does the graph of y=e^(-x^2) look like? Also, i know the integral is =integral(a,b) 2(pi)x*e^(-x^2) how do i evaulate the e^(-x^2) part?
 
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The graph of e-x^2 is the famous "Bell shaped curve"!

As far as the integral of x e-x^2 is concerned, try the substitution u= -x^2.
 


The graph of y=e^(-x^2) is a bell-shaped curve that decreases rapidly as x increases. It is also known as a Gaussian curve or a normal distribution curve.

To evaluate the integral of e^(-x^2), you can use the substitution method. Let u=-x^2, then du=-2x dx. Substitute these into the integral to get:
integral(a,b) 2(pi)x*e^(-x^2) dx = integral(a,b) 2(pi) ue^u du
This can now be evaluated using the power rule for integrals. Once you have the antiderivative, you can substitute back in for u and evaluate the integral from a to b. Alternatively, you can use a calculator or a software program to evaluate the integral numerically.
 
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