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## Homework Statement

Hi guys the question is: a mass spring-damper system is positioned between two rigid surfaces, if mass m = 200g, spring constant k = 80 Nm-1, and damping pot of coefficient 65 gs-1. The mass is pulled 5cm down from its equilibrium position and then released. What is the period of motion assuming the system is conservative?

## Homework Equations

period T = 2pi / omega >> (eq1)

and angular frequency omega^2 = (k / m) - (b/2m)^2 >>(eq2)

where k = spring constant

m = mass

b = coefficient of damping

## The Attempt at a Solution

using eq2 omega^2 = 80/200 - (65 / 2x 200)^2 => 0.4 -0.026 = 0.374

omega = sqrroot 0.374 = 0.061

plug this into eq1 => T = 2pi / 0.061 = 10.30 s

this value seems to high for me, can anybody see what I've done wrong? thanks in advanced.

Beige

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