Hi guys the question is: a mass spring-damper system is positioned between two rigid surfaces, if mass m = 200g, spring constant k = 80 Nm-1, and damping pot of coefficient 65 gs-1. The mass is pulled 5cm down from its equilibrium position and then released. What is the period of motion assuming the system is conservative?
period T = 2pi / omega >> (eq1)
and angular frequency omega^2 = (k / m) - (b/2m)^2 >>(eq2)
where k = spring constant
m = mass
b = coefficient of damping
The Attempt at a Solution
using eq2 omega^2 = 80/200 - (65 / 2x 200)^2 => 0.4 -0.026 = 0.374
omega = sqrroot 0.374 = 0.061
plug this into eq1 => T = 2pi / 0.061 = 10.30 s
this value seems to high for me, can anybody see what I've done wrong? thanks in advanced.