I Damping in a coupled pendulum system

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The discussion focuses on the effects of increased damping on the frequencies of coupled pendula, drawing an analogy with LC resonators. It suggests that adding a damper in parallel with the spring could influence the system's behavior, particularly affecting the "opposite" mode. Participants are encouraged to explore the implications of introducing arbitrary drag on each pendulum. Understanding these dynamics is presented as fundamental to grasping broader concepts in physics. The insights gained from this analysis are considered applicable across various physics scenarios.
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I was going through my old lab experiments ans stumbled upon a coupled pendulum experiment I did few years ago. Now That I have learnt about damping, I was wondering how a damping which would be present in the individual pendulums affect their coupling?
The beat frequency was equal to the difference in frequencies of the two normal modes. What would be the beat frequency in the case of damping present?
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From analogy with LC resonators, I think the increased damping will move the two frequencies further apart.
 
I think you should first think about putting a damper on (in parallel with) the spring. You know intuitively only the "opposite" mode would be affected. Work that through in detail.
Then put an arbitrary drag on each pendulum and work it out.
If you really understand this system you are looking at half of known physics IMHO. We use it over and over.
 
Thread 'Why higher speeds need more power if backward force is the same?'

Thread 'Why higher speeds need more power if backward force is the same?'

Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...
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