How Much Lateral Force Does a 70,000 lbs Truck Exert When Braking?

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A 70,000 lbs truck moving at 5 fps decelerates over 1 foot when brakes are applied, prompting a discussion on calculating the lateral force exerted during this time. The formula f = m * Δv / Δt is suggested for determining force, where m is mass, Δv is change in velocity, and Δt is time. Participants emphasize the importance of referencing physics textbooks for formulas related to uniform acceleration. Additionally, there is a request for individuals to attempt solving the problem independently before seeking assistance. The conversation underscores the need for foundational understanding in physics to tackle such calculations effectively.
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A truck weighing 70,000 lbs. is moving at 5 fps. on level ground. The brakes are applied and decelerates over the course of 1 foot. How much lateral force will be be exerting for that 1 second. Need a formula.
Thanks Signman
 
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f = m \Deltav / \Deltat

plugin values and done.
 
Signman, the formulas should be in your physics textbook, in the section dealing with uniform or constant acceleration. Try looking there.

You'll need to show an attempt at solving the problem before receiving help.

Sourab, please refrain from giving out the equations before people try solving the problem themselves.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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