Definite Integral of Product/Composite Function Given Graph

JessTheMess
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Homework Statement



Given the graph of f(x) shown below, find the value of the integral.
Photo attached.

Homework Equations


[/B]
23 5x·f(x2)dx

The Attempt at a Solution


[/B]
I tried integration by parts to simplify the problem, but finding the integral of the composite function (f(x2)) doesn't make much sense to me without knowing the actual function that represents f(x).

I also tried using the equation of the semi-circle to find it, but the integration got too complicated.

Does anyone have a hint on how to start the problem and/or deal with the composite function in the integral? Thank you!
 

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I would do the change of variables
$$t=x^2$$.
 
When I do u-substitution, I also run into a problem.

t=x^2
dt = 2xdx
dx = dt/2x

∫5xf(t)dt/2x

5/2 ∫f(t)dt

How do I take the integral of f(t) when I don’t know what function f(t) is?
 
JessTheMess said:
How do I take the integral of f(t) when I don’t know what function f(t) is?

I think you are supposed to work out what function ##f## is from the graph.
 
JessTheMess said:

Homework Statement



Given the graph of f(x) shown below, find the value of the integral.
Photo attached.

Homework Equations


[/B]
23 5x·f(x2)dx

The Attempt at a Solution


[/B]
I tried integration by parts to simplify the problem, but finding the integral of the composite function (f(x2)) doesn't make much sense to me without knowing the actual function that represents f(x).

I also tried using the equation of the semi-circle to find it, but the integration got too complicated.

Does anyone have a hint on how to start the problem and/or deal with the composite function in the integral? Thank you!

If one takes the most "obvious" form of the function ##f(x)##, the integral ##\int_3^2 5x f(x) \, dx## is negative; I hope you see why. However, if your integral, instead, really is ##\int_3^2 5x f(x^2) \, dx## (exactly as written) the integral is a pure imaginary number with a negative imaginary part.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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