- #1
lab-rat
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We are just starting integrals right now and I'm having trouble with this problem. I know how to solve a definite integral but I don't quite understand what is being asked here? Just wondering if anyone could let me know where I should start?
if∫0,3f(x)dx=12, ∫0,6f(x)dx=42,find ∫3,6(2f(x)−3)dx=12.
if∫0,3f(x)dx=12, ∫0,6f(x)dx=42,find ∫3,6(2f(x)−3)dx=12.