Definition of a multiple within a probability problem.

tempneff
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Below is a test problem I recently had in Probability class. I missed points on this problem (event B) because I counted 0 as a multiple of 3. But...0 is a multiple of 3 right?

I approached my professor with this concern and he told me that 0 is definately not a multiple of 3...
If I am right, can I have some advice on how to approach him again, or if I should at all. I lost 10% of the test grade which I could not afford..

Here's what I turned in...

1. Homework Statement

An urn contains 10 identical balls numbered 0,1,...9. A random experiment involves selecting a ball from the urn and noting the number of the ball. The events A,B,C are defined as follows:
A "number of the ball selected is odd."
B "number of the ball selected is a multiple of 3,"
C "number of the ball selected is less than 5,"

Find ##P(A),P(B),P(C),P(A\cup B), \text{ and } P(A\cup B \cup C).##

Homework Equations


Let ##\mathbb{Z}## denote the integers.
Say ##d## divides ##m##, equivalently, that ##m## is a multiple of ##d##, if there exists an integer ##q## such that ##m = qd##.

Let ##m=q=0 \text{ and } d=3##

then ##m=qd \Longrightarrow 0=0\times 3##

##\therefore 0 \text{ is a multiple of }3##

The Attempt at a Solution


[/B]
S= \{0,1,2,3,4,5,6,7,8,9\}

##A= \{1,3,5,7,9\} \hspace{20pt} B= \{ 0,3,6,9\} \hspace{20pt}C=\{0,1,2,3,4\}##

##P(A)=\frac{5}{10}\hspace{20pt}P(B)=\frac{4}{10}\hspace{20pt}P(C)=\frac{5}{10}##

##P(A \cup B) =\frac{7}{10} \hspace{20pt} P(A \cup B \cup C) = \frac{9}{10}##
 
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tempneff said:
Below is a test problem I recently had in Probability class. I missed points on this problem (event B) because I counted 0 as a multiple of 3. But...0 is a multiple of 3 right?

I approached my professor with this concern and he told me that 0 is definately not a multiple of 3...
If I am right, can I have some advice on how to approach him again, or if I should at all. I lost 10% of the test grade which I could not afford..

Here's what I turned in...

1. Homework Statement

An urn contains 10 identical balls numbered 0,1,...9. A random experiment involves selecting a ball from the urn and noting the number of the ball. The events A,B,C are defined as follows:
A "number of the ball selected is odd."
B "number of the ball selected is a multiple of 3,"
C "number of the ball selected is less than 5,"

Find ##P(A),P(B),P(C),P(A\cup B), \text{ and } P(A\cup B \cup C).##

...

I'm not sure how to approach him regarding this. Do you know a mathematician that he respects? (He must not be one himself.)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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