Deflection of tapered beam cantilever

AI Thread Summary
Calculating the deflection of a tapered cantilever beam with a varying cross-section is feasible by deriving an equation based on the relationship between bending moment, material properties, and the moment of inertia. The fundamental equation involves integrating the bending moment over the varying inertia along the beam's length. Users can validate their derived results through Finite Element Analysis (FEA) for accuracy. Empirical formulas from resources like Roark can also provide useful insights based on the beam's geometry. Engaging with these methods can yield a comprehensive understanding of the deflection behavior in tapered beams.
SJB
Messages
7
Reaction score
0
Hi and thank you for taking a look at my problem..

I'm very familiar with doing deflection calculations for beams of constant cross-section but I find myself needing to now do calculations on a beam of varying cross-section and I'm completely lost.

It's a relatively simple case in that the beam is a round/tubular, constant/symmetrical taper. It's supported in cantilever at the large end and the load is a single point load at the tip. I've attached a simple sketch if it helps.

As a starting point, is it even possible to derive an equation for the deflection of the beam or can this only be calculated by FEA? (excuse my ignorance!)

If anyone can offer any help/pointers/equations I would be very grateful.

Thanks for your time.

Simon
 

Attachments

Engineering news on Phys.org
This is certainly possible to derive eq'n of delection.

You will need to derive the deflection equation for you case, from equation:
E*I*d2y/dx2 = -M,where I is varying with position of section, and will be a function of x.
Therfore

E*d2y/dx2 = -M/Ix, and integrate this equation twice.

you will need to do this carefully and in the end you will get a big,scary expression of deflection.

You can definitely varify your result with FEA.

Take a look at Roark also for some empirical formula,depending upon ratio of both end area of inertias.
 
Hello Piygar,

Thank you for your reply, I'll give this a go and if successful will post back the equation in case it is useful to others.

Thanks

Simon
 
SJB: The cantilever tip deflection would be as follows, with x = 0 at the fixed support.

y_{\,\mathrm{max}}=\frac{1}{E}\int_{0}^{L}<br /> \int_{0}^{x}\frac{M(x)}{I(x)}\,dx\ dx
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top