A dentist's chair of mass 207kg is supported by a hydraulic lift having a large piston of cross-sectional area 1403.0cm^2. The dentist has a foot pedal attached to a small piston of cross-sectional area 78.0cm^2. What force must be applied to the small piston to raise the chair.
Fp/Ap = Fc/Ac
The Attempt at a Solution
Fp = Fc/Ac * Ap
Fp = 207kg/1403 * 78 = 112.78
Okay so I have already gotten the answer 112.78N but I don't understand a few things about this question...
- Why does Fp/Ap = Fc/Ac??
- Why is 207kg relate to 1403cm^2?
- What is the subscripts p and c???