Derivation of the moment of inertia eqn for a thin spherical shell

Click For Summary

Homework Help Overview

The discussion revolves around deriving the moment of inertia equation for a thin spherical shell, with references to a related equation for a hollow sphere. Participants explore algebraic approaches and limits in the context of rotational inertia.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to evaluate limits and apply L'Hopital's Rule but encounters indeterminate forms. Some participants suggest rewriting the equation in terms of a small parameter and using the binomial theorem for expansion. Questions arise regarding the assumptions made about the relationship between the outer and inner radii.

Discussion Status

The discussion includes various attempts to clarify the algebraic manipulations involved in the derivation. While some participants offer alternative approaches, there is no explicit consensus on the best method to proceed. The original poster expresses a breakthrough in understanding, though the details remain unclear.

Contextual Notes

Participants are navigating through algebraic complexities and the implications of limits as the inner radius approaches the outer radius. There is mention of external resources that may not be fully understood by all participants.

cubejunkies
Messages
33
Reaction score
0
So I've been trying to derive the moment of inertia equation for a thin spherical shell and I've slammed into a dead end algebraically. I was able to derive an equation for a hollow sphere:

I = (2/5) M (Ro^5 - Ri^5)/(Ro^3 - Ri^3)

where Ro is the distance to the very outside of the sphere and Ri is the distance to the inner thickness of the sphere if that makes sense.

I thought I could take the limit as Ri approached Ro, to yield the rotational inertia of a very thin spherical shell as I sought out for, however, I cannot evaluate the limits even if I used L'Hopital's Rule and derived the top and bottom separately because that would not allow me to escape the cursed indeterminant form of 0/0 which results every time until the denominator goes away to zero and then I'm really in a bad situation.

I saw a website http://scienceworld.wolfram.com/physics/MomentofInertiaSphericalShell.html which reduced the (Ro^5 - Ri^5)/(Ro^3 - Ri^3) term using a series decomposition of some sort, but I have no idea what they did and it's been a while since I've meddled with Taloy Series and stuff, so any help with this or an explanation of what they did would be greatly appreciated.

THANKS! :)
Anthony
 
Physics news on Phys.org
For a very thin shell, Ro=Ri(1+δ), and δ is very small compared to 1. Rewrite your equation in terms of Ri and δ. Remember the binomial theorem, http://en.wikipedia.org/wiki/Binomial_theorem and expand Ro5 and Ro3. Find the limit of I when \stackrel{δ}{\rightarrow}0.

But it is easy to get I by integration for a spherical surface.

ehild
 
Wait, why does Ro=Ri(1+δ) ? I don't get the (1+δ) part. I also tried expanding as they did on that webpage listed above, using Ro = Ri + r and expanding that, but I can't cancel stuff down like they did and the magical appearance of the factorials in the last step confuses me.

Thanks
Anthony
 
OH WAIT NEVERMIND haha I did some algebraic gymnastics and figured it out :)
 
You are an excellent sportsman!:wink: Don't you try the integration?

ehild
 

Similar threads

  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K