Derivative of y=ln|2-x-5x^2|: 1+10x/-2+x+5x^2

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y = ln|2-x-5x^2|

when you take the derivitve of somthing like this you can ignore the abs value signs right?

for the ans i got -1-10x / 2-x-5x^2
the answer is 1+10x / -2+x+5x^2

i obviously made some mistake some where because i have the same number just with different signs
 
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The two answers are the same. If the first answer is given by -a/b[/tex], the second one would be a/-b. The negative is just in a different place.
 
thanks i didt see that
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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