Derivatives of exponentials (calc II)

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Homework Statement


\frac{d}{dx}e^{ax^{3}}

I'm simply trying to determine whether or not I am doing these correctly and applying the chain rule properly.

Homework Equations


Chain rule et al.

The Attempt at a Solution



\frac{d}{dx}e^{ax^{3}}

e^{ax^{3}}\frac{d}{dx}ax^{3}

e^{ax^{3}}a(3)x^{2}

3ae^{ax^{3}}x^{2}

Does that look right to you? I am assuming "a" is just some constant, the book does not specify.
 
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Looks fine.
 
QuarkCharmer said:
Does that look right to you? I am assuming "a" is just some constant, the book does not specify.

Yes, this is correct. If you'd like proof take a look at (http://www.wolframalpha.com/input/?i=derivative+of+e^%28ax^3%29). "wolframalpha.com"[/URL] is a very good resource for checking your answers. Good luck!
 
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Okay great!

How about this one?

\frac{d}{dt}e^{tsin(2t)}

e^{tsin(2t)}\frac{d}{dt}tsin(2t)

e^{tsin(2t)}[sin(2t)+2cos(2t)]
 
Almost. The last term isn't correct.
 
Oh I think I just didn't type the "t". It's on my paper.

e^{tsin(2t)}[sin(2t)+2tcos(2t)]

Better?
 
Ayuh.
 
Thanks a bunch!
 
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